RAIMAD

Function overlap from raimad.iters

def overlap(n: int, seq: collections.abc.Sequence[~T]) -> collections.abc.Iterable[collections.abc.Iterable[~T]]

Iterate n items at a time, with overlap.

overlap(3, [1,2,3,4,5]) = [
    [1,2,3],
    [2,3,4],
    [3,4,5],
    ]
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def overlap(n: int, seq: Sequence[T]) -> Iterable[Iterable[T]]:
    """
    Iterate n items at a time, with overlap.

    overlap(3, [1,2,3,4,5]) = [
        [1,2,3],
        [2,3,4],
        [3,4,5],
        ]
    """
    return zip(*[seq[offset:] for offset in range(n)])